Diff for "AmdahlsLaw" - Dr. A's Wiki

Differences between revisions 1 and 25 (spanning 24 versions)

latex2( $S p e e d u p = \frac{P e r f o r m a n c e u s i n g e n h a n c e m e n t w h e n p o s s i b l e}{P e r f o r m a n c e w i t h o u t e n h a n c e m e n t}$ )

See SpeedUp

Notice that we are talking about the entire task here and that performance (speedup) is defined in terms of execution time! So we have to define the following:

latex2( $S p e e d u p O v e r a l l = \frac{O l d E x e c u t i o n T i m e}{N e w E x e c u t i o n T i m e}$ )

This gives a new Execution time of

latex2( $N e w E x e c T i m e = O l d E x e c T i m e (1 - F r a c t i o n E n h a n c e d + \frac{F r a c t i o n E n h a n c e d}{S p e e d u p E n h a n c e d})$ )

So we have latex2( $S p e e d u p O v e r a l l = \frac{1}{1 - F r a c t i o n E n h a n c e d + \frac{F r a c t i o n E n h a n c e d}{S p e e d u p E n h a n c e d}}$ )

Back to ComputerTerms

-  ⇤ ← Revision 1 as of 2004-01-25 18:20:24 → 
  Size: 301
  Editor: yakko
  Comment:
+   ← Revision 25 as of 2005-06-28 01:19:15 → ⇥
  Size: 706
  Editor: yakko
  Comment:
-Deletions are marked like this.
+Additions are marked like this.
 Line 3:
-{{{
           Performance for entire task using the enhancement when possible
Speedup = -----------------------------------------------------------------
              Performance for entire taks without using the enhancement
}}}
+[[latex2( $S p e e d u p = \frac{P e r f o r m a n c e u s i n g e n h a n c e m e n t w h e n p o s s i b l e}{P e r f o r m a n c e w i t h o u t e n h a n c e m e n t}$ )]]
-Line 11:
+Line 7:
+Notice that we are talking about the entire task here and that performance (speedup) is defined in terms of execution time! So we have to define the following:

[[latex2( $S p e e d u p O v e r a l l = \frac{O l d E x e c u t i o n T i m e}{N e w E x e c u t i o n T i m e}$ )]] 

This gives a new Execution time of 

[[latex2( $N e w E x e c T i m e = O l d E x e c T i m e (1 - F r a c t i o n E n h a n c e d + \frac{F r a c t i o n E n h a n c e d}{S p e e d u p E n h a n c e d})$ )]]

So we have
[[latex2( $S p e e d u p O v e r a l l = \frac{1}{1 - F r a c t i o n E n h a n c e d + \frac{F r a c t i o n E n h a n c e d}{S p e e d u p E n h a n c e d}}$ )]]