Diff for "AmdahlsLaw"

Differences between revisions 24 and 26 (spanning 2 versions)

Notice that we are talking about the entire task here and that performance (speedup) is defined in terms of execution time! So we have to define the following:

latex2($$SpeedupOverall = \frac{Old~Execution~Time}{New~Execution~Time}$$)

This gives a new Execution time of latex2($$New~Exec~Time = Old~Exec~Time \left( 1 - FractionEnhanced + \frac{FractionEnhanced}{SpeedupEnhanced}\right)$$)

So we have latex2($$SpeedupOverall=\frac{1}{1-FractionEnhanced + \frac{FractionEnhanced}{SpeedupEnhanced}}$$)

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-  ⇤ ← Revision 24 as of 2005-06-28 01:18:43 → 
  Size: 709
  Editor: yakko
  Comment:
+   ← Revision 26 as of 2005-06-28 01:39:51 → ⇥
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  Editor: yakko
  Comment:
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-This gives a new Execution time of 

[[latex2($$New~Exec~Time = Old~Exec~Time \left( 1 - FractionEnhanced + \frac{FractionEnhanced}{SpeedupEnhanced}\right)$$)]]
+This gives a new Execution time of [[latex2($$New~Exec~Time = Old~Exec~Time \left( 1 - FractionEnhanced + \frac{FractionEnhanced}{SpeedupEnhanced}\right)$$)]]
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-[[latex2($$SpeedupOverall=\frac{1}{1-FractionEnhanced + \frac{FractionEnhanced}{SpeedupEnhanced}})]]
+[[latex2($$SpeedupOverall=\frac{1}{1-FractionEnhanced + \frac{FractionEnhanced}{SpeedupEnhanced}}$$)]]