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Normalize: Given a reference execution time A, take the execution time you have (B) and divide it by the reference execution time. What you get is a normalized execution time of B with respect to A.
Excution time of B Normalized(B) = ---------------------------- Reference Execution Time A
Given several programs P1, P2, ..., Pn, the average normalized execution time is
For (i=1; i++, <= n) { P *= Normalized(Pi) } return P^(1/n) or _____________ / n n / __ \/ || Normalized(Pi) i=1
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